## Elementary Geometry for College Students (5th Edition)

Using method ASA with 2 congruent pair angles and 1 congruent pair of included sides, we can prove that $\triangle ABC\cong\triangle DBC$.
It is given that 1) $\angle A\cong\angle D$ 2) $\overline{AB}\cong\overline{BD}$ 3) $\angle 1\cong\angle 2$ 2 angles of $\triangle ABC$ are congruent with 2 angles of $\triangle DBC$ and 1 included side of $\triangle ABC$ is congruent with 1 included side of $\triangle DBC$. Therefore, according to method ASA, $\triangle ABC\cong\triangle DBC$.