Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 2 - Section 2.1 - The Parallel Postulate and Special Angles - Exercises - Page 80: 25

Answer

$m\angle{ACD}$ = 93$^{\circ}$

Work Step by Step

1. Construct a line through point C such that it is parallel to line AB and line DE. Name a point above point C (here, I will use X). 2. Alternate interior angles are congruent. Therefore, $\angle{BAC}\;\cong\;\angle{ACX}$ and $\angle{CDE}\;\cong\;\angle{DCX}$. 3. Congruent angles have equivalent measures. Therefore, $m\angle{BAC}\;=\;m\angle{ACX}$ and $m\angle{CDE}\;=\;m\angle{DCX}$. 4. We are given that $m\angle{BAC}\;+\;m\angle{CDE}\;=\;93^{\circ}$. By substitution, $m\angle{ACX}\;+\;m\angle{DCX}\;=\;93^{\circ}$. 5. $m\angle{ACX}\;+\;m\angle{DCX}$ also equals $m\angle{ACD}$. 6. Therefore, $m\angle{ACD}=93^{\circ}$.
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