Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Test - Page 534: 3a

Answer

$1$

Work Step by Step

$\tan45^{\circ}=\frac{\sin45^{\circ}}{\cos45^{\circ}}$ $\tan45^{\circ}=\frac{\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}$ $\tan45^{\circ}=1$
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