Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Test - Page 534: 2b

Answer

$\frac{3}{5}$

Work Step by Step

$\sin\alpha=\frac{opposite}{hypotenuse}=\frac{6}{10}=\frac{3}{5}$
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