Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 527: 13

Answer

$A \approx 11.6$ ft$^{2}$

Work Step by Step

$A = \frac{1}{2}absin(C)$ $A = (0.5)(6)(6)sin(40)$ (We know that both $a$ and $b$ are the same as this is an isosceles triangle) $= (0.5)(36)sin(40)$ by GDC / calculator $= 11.5701...$ ft$^{2}$ $\approx 11.6$ ft$^{2}$
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