#### Answer

$41.6$ in.$^{2}$

#### Work Step by Step

$A=\frac{1}{2}(8)(12)\sin60^{\circ}$
$A=48\sin60^{\circ}$
$A\approx41.6$ in.$^{2}$

Published by
Brooks Cole

ISBN 10:
1439047901

ISBN 13:
978-1-43904-790-3

$41.6$ in.$^{2}$

$A=\frac{1}{2}(8)(12)\sin60^{\circ}$
$A=48\sin60^{\circ}$
$A\approx41.6$ in.$^{2}$

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