Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 527: 12

Answer

$41.6$ in.$^{2}$

Work Step by Step

$A=\frac{1}{2}(8)(12)\sin60^{\circ}$ $A=48\sin60^{\circ}$ $A\approx41.6$ in.$^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.