#### Answer

The distance from the plane to touch down is $\approx 1376.8$ ft.

#### Work Step by Step

1. Use the sine law to solve for $x$
$\frac{x}{sin90} = \frac{120}{sin5}$
$x = \frac{120sin90}{sin5}$
$x = \frac{120}{0.087155...}$
$x = 1376.845...$ ft
$x \approx 1376.8$ ft