Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.3 - The Tangent Ratio and Other Ratios - Exercises - Page 518: 18

Answer

$a\approx15.6$ $c\approx25.4$

Work Step by Step

$\sin52^{\circ}=\frac{20}{c}$ $c=\frac{20}{\sin52^{\circ}}$ $c\approx25.4$ $\tan52^{\circ}=\frac{20}{a}$ $a=\frac{20}{\tan52^{\circ}}$ $a\approx15.6$
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