Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.3 - The Tangent Ratio and Other Ratios - Exercises - Page 517: 1

Answer

$\tan\alpha=\frac{3}{4}$ $\tan\beta=\frac{4}{3}$

Work Step by Step

$\tan\alpha=\frac{opposite}{adjacent}=\frac{3}{4}$ $\tan\beta=\frac{opposite}{adjacent}=\frac{4}{3}$
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