Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.2 - The Cosine Ratio and Applications - Exercises - Page 509: 7

Answer

sin α = $\frac{a}{c}$ cos β = $\frac{a}{c}$ thus sin α = cos β

Work Step by Step

Lets take question 1 diagram: as we know sin α = $\frac{opposite}{hypotenus}$ for question 1 , sin α = $\frac{5}{13}$ cos β = $\frac{adjacent}{hypotenus}$ for question 1 , cos β = $\frac{5}{13}$ Therefore we can say that sin α = cos β = $\frac{5}{13}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.