Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises: 29

Answer

$103.5$ ft

Work Step by Step

Let $d$ be the distance between Danny and the balloon. $\sin75^{\circ}=\frac{100}{d}$ $d=\frac{100}{\sin75^{\circ}}$ $d\approx103.5$

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