Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 502: 2

Answer

$\sin\alpha=\frac{3}{5}$ $\sin\beta=\frac{4}{5}$

Work Step by Step

$\sin\alpha=\frac{opposite}{hypotenuse}=\frac{6}{10}=\frac{3}{5}$ $\sin\beta=\frac{opposite}{hypotenuse}=\frac{8}{10}=\frac{4}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.