Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 502: 18

Answer

$c\approx14.2$ in. $d\approx7.6$ in.

Work Step by Step

$\sin58^{\circ}=\frac{12}{c}$ $c=\frac{12}{\sin58^{\circ}}$ $c\approx14.2$ Using Pythagorean Theorem to find $d$. $d=\sqrt {c^{2}-12^{2}}$ $d\approx\sqrt{14.2^{2}-12^{2}}$ $d\approx7.6$
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