Elementary Geometry for College Students (5th Edition)

$a\approx10.9$ ft $b\approx11.7$ ft
$\sin47^{\circ}=\frac{b}{16}$ $b=16\times\sin47^{\circ}$ $b\approx11.7$ Using Pythagorean Theorem to find $a$. $a=\sqrt {16^{2}-b^{2}}$ $a\approx\sqrt{16^{2}-11.7^{2}}$ $a\approx10.9$