Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Review Exercises - Page 534: 28

Answer

$\approx$ 106°

Work Step by Step

$\frac{longer diagonal}{2}$= $\frac{shorter diagonal}{2}$ $\times$ tan $\frac{obtuse angle}{2}$ 8 in. = 6 in. $\times$ tan $\frac{obtuse angle}{2}$ tan $\frac{obtuse angle}{2}$ = $\frac{4}{3}$ $\frac{obtuse angle}{2}$ $\approx$ 53° obtuse angle $\approx$ 106°
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