#### Answer

The rocket is $\approx 866$ ft in the air after 5 seconds.

#### Work Step by Step

1. Find the value of x using the sine law
$\frac{x}{sin60} = \frac{200}{sin90}$
$ x = \frac{200sin60}{1}$
$ x = 173.2050....$ ft/s
2. Multiply the x value by the number of seconds asked by the question (In this cause, the question is asking the height of the rocket after 5 seconds)
Let $H =$ Height of the rocket after $5$ seconds
$H = 173.2050... \times x$
$H = 173.2050... \times 5$
$H = 866.0254...$
$H \approx 866$ ft