#### Answer

$(6, -1)$

#### Work Step by Step

$2x + y =11$
$3x + 2y =16$
When we multiply the first equation by 2, the system becomes
$4x + 2y = 22$
$3x + 2y = 16$
Subtracting these equations yields $x = 6$. Substituting $x = 6$ into the first equation, we get $12 +y = 11$. Then $y = −1$. So the solution is $(6, −1)$.