#### Answer

bx+ay = ab is the required equation

#### Work Step by Step

The line contains(0,b) and (a,0)
To find the equation of the line.
To use the point slope form, we need to find the slope of the line using (-2,0) and (4,3)
m = $\frac{y2-y1}{x2-x1}$ = $\frac{0-b}{a-0}$ =$\frac{-b}{a}$
then, y-y1 = m(x-x1)
y-b =$\frac{-b}{a}$ (x-0)
y - b= $\frac{-b}{a}$ x
ay - ab = -bx
bx+ay = ab