# Chapter 10 - Section 10.5 - Equations of Lines - Exercises: 13

2x-3y = 3

#### Work Step by Step

The line contains(0,-1) and (3,1) To find the equation of the line. To use the point slope form, we need to find the slope of the line using (0,-1) and (3,1) m = $\frac{y2-y1}{x2-x1}$ = $\frac{1+1}{3-0}$ =$\frac{2}{3}$ then, y-y1 = m(x-x1) y-(-1) =$\frac{2}{3}$ (x-0) y+1 = $\frac{2}{3}$ x 3(y+1) = 2x 3y + 3=2x 2x-3y = 3

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