Answer
The line described has a slope of -2/3 and a point of $(-2,1)$
Work Step by Step
We find the slope of the perpendicular line:
$m = \frac{y_2-y_1}{x_2-x_1} = \frac{3-0}{0-(-2)} = 3/2$
Thus, since the slope of perpendicular lines are opposite reciprocals, this slope is: -2/3.
In order to sketch this given line, start at the point $(-2,1)$ in the coordinate plane. Next, recalling that slope is rise over run, use this point to find another point on the graph. In this case, start at $(-2,1)$ and go down 2 and over 3 to the point $(1,-1)$. Finally, draw a straight line that goes through both points.