## Elementary Geometry for College Students (5th Edition)

$x=8$ $m\angle(2)=56^{\circ}$
Since $\angle(2)$ equals $\angle(4)$, you can set up the same equation from the last exercise with the angle measurements: $6x+8=7x$ $8=(7x-6x)=x$ Now you can plug in the value for $x$ again to find $m\angle(2)$: $m\angle(2)=(6x+8)^{\circ}$ $m\angle(2)=(6(8)+8)^{\circ}$ $m\angle(2)=(48+8)^{\circ}$ $m\angle(2)=56^{\circ}$