Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 1 - Section 1.4 - Angles and Their Relationships - Exercises: 31

Answer

x=143$^{\circ}$

Work Step by Step

x=(90$^{\circ}$-$\angle$PNQ)+92$^{\circ}$ x=(90$^{\circ}$-39$^{\circ}$)+92$^{\circ}$ x=51$^{\circ}$+92$^{\circ}$ x=143$^{\circ}$
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