Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 1 - Section 1.3 - Early Definitions and Postulates - Exercises: 28c

Answer

$\overline{AC}$ $\ncong$ $\overline{CD}$

Work Step by Step

In part (a), we determined that $\overline{AB}$ $\cong$ $\overline{BC}$ $\cong$ $\overline{CD}$. Using the Segment Addition Postulate $\overline{AB}$ + $\overline{BC}$ $\cong$ $\overline{AC}$. Therefore, $\overline{AC}$ is twice as long as $\overline{CD}$.
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