Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Appendix A - A.4 - Quadratic Equations - Exercises - Page 560: 25

Answer

$x=1.52; x=-0.92$

Work Step by Step

$x=\frac{-b+\sqrt (b^{2}-4ac)}{2a}$ $x=\frac{-b-\sqrt (b^{2}-4ac)}{2a}$ a= 5 b= -3 c= -7 $x=\frac{3+12.21}{10}$ $x=\frac{3-12.21}{10}$
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