Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Appendix A - A.4 - Quadratic Equations - Exercises - Page 560: 17

Answer

$x = \frac{1}{3}, \frac{1}{2}$

Work Step by Step

$6x^{2} = 5x - 1$ $6x^{2} - 5x + 1 = 0$ Find two numbers that will multiply together to get $6$ and can be added together to get $-5$. $= -2$ and $-3$ $6x^{2} - 3x - 2x + 1 = 0$ $3x(2x - 1) - 1(2x-1) = 0$ $(3x - 1)(2x-1) = 0$ $3x - 1 = 0$ $3x = 1$ $x = \frac{1}{3}$ $2x - 1 = 0$ $2x = 1$ $x = \frac{1}{2}$ $x = \frac{1}{3}, \frac{1}{2}$
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