Answer
$(x,y,z)=(2,-7,-32)$
Work Step by Step
Consider $x=2$
and $2x+y=-3 \implies 2(2)+y=-3$
This implies $y=-7$
Now, $-3x-4y+z=-10 \implies -3(2)-4(-7)+z=-10$
or, $z=-32$
Our result is : $(x,y,z)=(2,-7,-32)$
Linear Algebra: A Modern Introduction
by Poole, David
Published by
Cengage Learning
ISBN 10:
1285463242
ISBN 13:
978-1-28546-324-7
Chapter 2 - Systems of Linear Equations - 2.1 Introduction to Systems of Linear Equations - Exercises 2.1 - Page 63: 25
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