University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.6 - The Chain Rule - Exercises - Page 158: 11

Answer

$\frac{dy}{dx} = (1 - \frac{x}{7})^{-8}$

Work Step by Step

$y = u^{-7}$ where, $u = (1 - \frac{x}{7})$ Now, $\frac{dy}{du} = -7u^{-8}$ and, $\frac{du}{dx} = -\frac{1}{7}$ So, $\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}$ $\frac{dy}{dx} =u^{-8}$ $\frac{dy}{dx} = (1 - \frac{x}{7})^{-8}$
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