University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.6 - The Chain Rule - Exercises: 1

Answer

$\frac{dy}{dx} = 12x^{3}$

Work Step by Step

$\frac{dy}{dx} = \frac{dy}{du}*\frac{du}{dx}$ Now, $\frac{dy}{du} = \frac{d(6u-9)}{du} = 6$ And, $\frac{du}{dx} = \frac{d (\frac{1}{2})x^{4}}{dx} = 2x^{3}$ Now, $\frac{dy}{dx} = 12x^{3}$
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