Answer
$f'(x) = x^{-2}$
So,
$f'(\sqrt 3) = \frac{1}{(\sqrt 3)^{2}} = \frac{1}{3}$
Work Step by Step
$f(x) = 1 - \frac{1}{x}$
Therefore,
$f'(x) = 0 - (-1)x^(-1-1)$
$f'(x) = x^{-2}$
So,
$f'(\sqrt 3) = \frac{1}{(\sqrt 3)^{2}} = \frac{1}{3}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.2 - The Derivative as a Function - Exercises - Page 125: 20
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