Answer
$\frac{dy}{dx}=\frac{-2x-y+5}{x+2y}$
Work Step by Step
We are given that:
$x^2+xy+y^2-5x=2$
differentiate the above term:
$2x+x\frac{dy}{dx}+y+2y\frac{dy}{dx}-5=0$
$\frac{dy}{dx}=\frac{-2x-y+5}{x+2y}$
Thus the final answer is: $\frac{dy}{dx}=\frac{-2x-y+5}{x+2y}$
