Answer
$\frac{dy}{dx}=-\frac{(y+2)}{(x+3)}$
Work Step by Step
We are given that:
$xy+2x+3y=1$
differentiate the above term:
$y+x\frac{dy}{dx}+2+3\frac{dy}{dx}=0$
$(x+3)\frac{dy}{dx}=-(y+2)$
$\frac{dy}{dx}=-\frac{(y+2)}{(x+3)}$
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