Answer
$\frac{dy}{dt}=-\ln(8)\times 8^{(-t)}$
Work Step by Step
$y=8^{-t}=e^{-t\times\ln(8)}$
On differentiating both sides:
$\frac{dy}{dt}=-\ln(8)\times e^{-t\times\ln(8)}$
$\frac{dy}{dt}=-\ln(8)\times 8^{(-t)}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Practice Exercises - Page 202: 49
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