Answer
$\frac{dy}{dx}={x}e^{{4}{x}}$
Work Step by Step
$y=\frac{1}{4}{x}e^{4x}-\frac{1}{16}e^{4x}=(\frac{1}{4}{x}-\frac{1}{16})e^{4x}$
on differentiating both sides:
$\frac{dy}{dx}=\frac{d((\frac{1}{4}{x}-\frac{1}{16})e^{4x})}{dx}$
$\frac{dy}{dx}=(\frac{1}{4}{x}-\frac{1}{16})\times4e^{4x}+(\frac{1}{4})e^{4x}$
$\frac{dy}{dx}={x}e^{{4}{x}}$
