University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises - Page 202: 4

Answer

$7x^6+\sqrt 7$

Work Step by Step

$y=x^7+\sqrt 7 x-\frac{1}{\pi+1}$ $y'=7x^6+\sqrt 7-0=7x^6+\sqrt 7$
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