Answer
a) 0
b) 0
c) 9
d) 3
Work Step by Step
a)$ \lim\limits_{x \to 4}(g(x)+3) = (-3+3) = 0$
b)$ \lim\limits_{x \to 4}xf(x) = 4(0) = 0$
c) $ \lim\limits_{x \to 4}(g(x))^{2}= (-3)^{2} = 9$
d)$ \lim\limits_{x \to 4}\frac{g(x)}{f(x)-1}= \frac{-3}{0-1} = 3$
