University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises: 44

Answer

$\lim\limits_{x \to \frac{\pi}{4}}\sin^{2}x = \frac{1}{2} = 0.5$

Work Step by Step

$\lim\limits_{x \to \frac{\pi}{4}}\sin{x}= \sin{\frac{\pi}{4}} = \frac{1}{\sqrt 2} = 0.707$ So, $\lim\limits_{x \to \frac{\pi}{4}}\sin^{2}{x} = (\frac{1}{\sqrt 2})^{2} = \frac{1}{2} = 0.5$
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