Answer
$\lim\limits_{x \to -\frac{1}{2}}4x(3x + 4)^{2} =-12.5=-\frac{25}{2}$
Work Step by Step
$\lim\limits_{x \to -\frac{1}{2}}4x(3x + 4)^{2} = \lim\limits_{x \to -0.5}(36x^{3} + 96x^{2} + 64x)$
= $36\lim\limits_{x \to -0.5}x^{3} + 96\lim\limits_{x \to -0.5}x^{2} + 64\lim\limits_{x \to -0.5}x$
= $36(-0.5)^{3} + 96(-0.5)^{2} + 64(-0.5)$ = -12.5
