University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises: 13

Answer

$\lim\limits_{t \to 6} 8(t-5)(t-7) = -8$

Work Step by Step

$\lim\limits_{t \to 6} 8(t-5)(t-7) = \lim\limits_{t \to 6} (8t^{2} -96t +280)$ = $\lim\limits_{t \to 6}8t^{2} - \lim\limits_{t \to 6}96t +\lim\limits_{t \to 6}280$ = $8*6^{2} - 96*6 + 280$ $= -8$
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