## University Calculus: Early Transcendentals (3rd Edition)

$\lim\limits_{x \to 2} (-x^{2} + 5x -2)$ =4
$\lim\limits_{x \to 2} (-x^{2} + 5x -2)$ = - $\lim\limits_{x \to 2}x^{2} + \lim\limits_{x \to 2} 5x - \lim\limits_{x \to 2}2$ $= -(2^{2}) + 5*2 - 2$ $= -4+10-2$ $=4$