Answer
Graph is symmetric with respect to the origin.
The graph of the given function $\ y=-x^3\ $ is decreasing on $\ (-\infty,\infty)\ $. There is no interval on which the function is increasing.
Work Step by Step
$\mathrm{First\:Part:}\:\:$ A function $\ f\ $ defined on an interval is increasing on $\ (a, b)\ $ if for every $\ x_1, x_2\ $ $\in$ $(a, b)$ $\ x_1\le x_2\ $ implies that $\ f(x_1)\le f(x_2).\ $
A function $\ f\ $ defined on an interval is decreasing on $\ (a, b)\ $ if for every $\ x_1, x_2\ $ $\in$ $(a, b)$ $\ x_1\le x_2\ $ implies that $\ f(x_1)\ge f(x_2).\ $
First of all create a table with a few points to sketch the graph.
$\mathrm{See\:the\:table\:and\:graph\:above.}$
$\mathrm{Second\:Part:}\:\:$ Graph is symmetric with respect to the origin.
$\mathrm{Third\:Part:}\:\:$ The graph of the given function $\ y=-x^3\ $ is decreasing on $\ (-\infty,\infty)\ $. There is no interval on which the function is increasing.
