Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 51

Answer

The function is odd.

Work Step by Step

$g(x)=x^3+x$ $g(-x)=(-x)^3-x=-x^3-x$ $-g(x)=-x^3-x$ $g(x)\ne g(-x)$ - The function is not even. $g(-x)=-g(x)$ The function is odd.
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