Answer
$\frac{11e-48}{12e}$
Work Step by Step
$\int_CF.dr=\int_0^{1}2te^{-t}dt+\int_0^{1}-3t^5-t^2-t^3dt$
$=[-2te^{-t}-2e^{-t}]_0^{1}+[-\frac{t^6}{2}-\frac{t^3}{3}-\frac{t^4}{4}]_0^{1}$
$=2-\frac{4}{e}-\frac{13}{12}$
$=\frac{11e-48}{12e}$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 16 - Vector Calculus - Review - Exercises - Page 1161: 9
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