Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 16 - Vector Calculus - 16.7 Exercises - Page 1144: 3

Answer

$900 \pi$

Work Step by Step

The flux through a surface can be defined only when the surface is orientable. We know that $\iint_S F \cdot dS=\iint_S F \cdot n dS$ Here, $n$ denotes the unit vector. Since, $\iint_S f(x,y,z) dS \approx \Sigma_{i=1}^n f(\overline(x), \overline(y), \overline(z)) AS_i$ Here, the four parts have the same surface area and the area of each of the four quarter cylinders is $\dfrac{4 \pi r^2}{8}=\dfrac{ \pi (50)}{2}= 25\pi$ Thus, $\iint_S F(x,y,z) dS =25 \pi[7+8+9+12]=900 \pi$
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