Answer
$\frac{1}{54} (145^{3/2}-1)$
Work Step by Step
$\int_Cy^3 \, ds = \int_0^2 t^3 \sqrt{9t^4 + 1} \, dt = \frac{1}{54} (145^{3/2}-1)$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 16 - Vector Calculus - 16.2 Exercises - Page 1096: 1
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