Answer
$\dfrac{2}{3}$
Work Step by Step
Consider $V=\int_{0}^{2} \int_{0}^{y}
int_0^{(2-y/2)} dz \space dx \space dy$
or, $=\int_{0}^{2} \int_{0}^{y} (1-\dfrac{y}{2}) dx dy$
or, $=\int_0^2 (y-\dfrac{y^2}{2}) dy$
or, $Volume =\dfrac{2}{3}$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 15 - Multiple Integrals - Review - Exercises - Page 1075: 31
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