Answer
$176$
Work Step by Step
Consider $V=\int_{0}^{2} \int_{1}^{4} x^2+4y^2 dy \space dx$
or, $=\int_{0}^{2} (x^2y+\dfrac{4y^3}{3})_1^4 dx$
or, $=\int_0^2 3x^2 +84 dx$
or, $=(x^3+84x)_0^2 $
or, $=8+168$
or, $Volume =176$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 15 - Multiple Integrals - Review - Exercises - Page 1075: 29
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