Answer
$\int^1_0 \int^{s^{2}}_0 cos(s^3)dtds = \frac{1}{3}sin1$
Work Step by Step
$\int^1_0 \int^{s^{2}}_0 cos(s^3)dtds = \int^1_0[tcos(s^3)]^{t=s^2}_{t=0}ds = \int^1_0s^2cos(s^3)ds = \frac{1}{3}sin(s^3)]^1_0 = \frac{1}{3}(sin1 - sin0) = \frac{1}{3}sin1$
