Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 14 - Partial Derivatives - Review - Exercises - Page 993: 22

Answer

$v_{rr}=0$ $v_{rs}=-sin(s+2t)$ $v_{rt}=-2sin(s+2t)$ $v_{sr}=-sin(s+2t)$ $v_{ss}=-rcos(s+2t)$ $v_{st}=-2rcos(s+2t)$ $v_{tr}=-2sin(s+2t)$ $v_{ts}=-2rcos(s+2t)$ $v_{tt}=-4rcos(s+2t)$

Work Step by Step

Given: $v=rcos(s+2t)$ $v_{rr}=0$ $v_{rs}=-sin(s+2t)$ $v_{rt}=-2sin(s+2t)$ $v_{sr}=-sin(s+2t)$ $v_{ss}=-rcos(s+2t)$ $v_{st}=-2rcos(s+2t)$ $v_{tr}=-2sin(s+2t)$ $v_{ts}=-2rcos(s+2t)$ $v_{tt}=-4rcos(s+2t)$
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