Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 14 - Partial Derivatives - 14.6 Exercises - Page 967: 19

Answer

$\dfrac{2}{5}$

Work Step by Step

Formula to calculate the directional derivative: $D_uf=\nabla f(x,y) \cdot u$ or, $D_uf=\nabla f(x,y) \cdot \dfrac{v}{|v|}$ At $(2,8)$ $D_uf (2,8)=(\dfrac{y}{2\sqrt{xy}},\dfrac{x}{2\sqrt{xy}}) \cdot (\dfrac{3}{5},\dfrac{-4}{5})$ $D_uf (2,8)=(1,\dfrac{1}{4}) \cdot (\dfrac{3}{5},\dfrac{-4}{5})$ Hence, $D_uf (2,8)=\dfrac{2}{5}$
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