Answer
$dm=5p^{4}q^{3}dp+3p^{5}q^{2}dq$
Work Step by Step
$dm=\displaystyle \frac{\partial m}{\partial p}dp+\frac{\partial m}{\partial q}dq$
$m=p^{5}q^{3}$
$\displaystyle \frac{\partial m}{\partial p}dp=5p^{4}q^{3}dp$
$\displaystyle \frac{\partial m}{\partial q}dq=3p^{5}q^{2}dq$
$dm=5p^{4}q^{3}dp+3p^{5}q^{2}dq$
